x^2+2x+5=3

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Solution for x^2+2x+5=3 equation: 



x^2+2x+5=3

We move all terms to the left:

x^2+2x+5-(3)=0

We add all the numbers together, and all the variables

x^2+2x+2=0

a = 1; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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